Let’s write the reaction equation:
Zn + H2SO4 = ZnSO4 + H2 ↑
Let’s find the amount of zinc substance:
ω (pure zinc) = 100% – 20% = 80% = 0.8
m (Zn) = m (technical zinc) * ω (pure zinc) = 80 * 0.8 = 64 g
n (Zn) = m (Zn) / Mr (Zn) = 64/65 = (about) 0.985 mol;
Let’s find the volume of released hydrogen:
n (H2) = n (Zn) = 0.985 mol;
V (H2) = n (H2) * Vm = 0.985 * 22.4 = (approximately) 22.1 L
Answer: 22.1 liters.
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