80 ml of water was added to 200 grams of 40% sulfuric acid solution. what is the percentage

80 ml of water was added to 200 grams of 40% sulfuric acid solution. what is the percentage of sulfuric acid in the newly obtained solution?

1. Calculate the mass of the acid contained in the original solution:

m (H2SO4) = wout (H2SO4) * mout (solution) = 0.4 * 200 = 80 g;

2. find the mass of the solution after dilution:

ρ (H2O) = 1 g / ml;

m (H2O) = ρ (H2O) * V (H2O) = 1 * 80 = 80 g;

mnew (solution) = mout (solution) + madd (H2O) = 200 + 80 = 280 g;

3. Determine the mass fraction of sulfuric acid in a diluted solution:

wnew (H2SO4) = m (H2SO4): mnew (solution) = 80: 280 = 0.2857 or 28.57%.

Answer: 28.57%.