800 grams of water intake at 100 degrees is poured into water weighing 1.5 kg, having a temperature of 20 degrees.

800 grams of water intake at 100 degrees is poured into water weighing 1.5 kg, having a temperature of 20 degrees. How much heat is transferred to the environment by the time the temperature of the mixture reaches 35 degrees.

This is a pretty interesting and easy task.

In solving it, we will use formulas.

So, let’s start solving this problem.

We will have to find Q. Q = differences between 2 more Q.

In the formula, it looks like this:

Q = Q2 – Q1.

In turn, Q1 = c * m1 (t – t1).

And Q2 = c * (t2 – t).

It turns out that Q1 = 94500 J.

In turn, it turns out that Q2 = 218400 J.

And it turns out that Q = 123,900 J.

Thus, we found what was required of us to find.

That is, we solved the problem correctly. This will be the answer.