80g of magnesium reacts with hydrochloric acid. Determine the mass of the salt obtained.
August 18, 2021 | education
| Let’s write the reaction equation:
Mg + 2HCl = MgCl2 + H2 ↑
Let’s find the amount of magnesium substance:
v (Mg) = m (Mg) / M (Mg) = 80/24 (mol).
According to the reaction equation, from 1 mol of Mg, 1 mol of MgCl2 is formed, therefore:
v (MgCl2) = v (Mg) = 80/24 (mol).
Thus, the mass of the obtained magnesium chloride salt is:
m (MgCl2) = v (MgCl2) * M (MgCl2) = (80/24) * 95 = 316. (6) = 316.7 (g).
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