9.8 gm of orthophosphoric acid reacts with sodium hydroxide. Calculate the mass of the salt formed.

Given:
m (H3PO4) = 9.8 g
To find:
m (Na3PO4)
Decision:
3NaOH + H3PO4 = Na3PO4 + 3H2O
n (H3PO4) = m / M = 9.8 g / 98 g / mol = 0.1 mol
n (H3PO4): n (Na3PO4) = 1: 1
n (Na3PO4) = 0.1 mol
m (Na3PO4) = n * M = 0.1 mol * 164 g / mol = 16.4 g
Answer: 16.4 g



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