98 g of a sulfuric acid solution was mixed with an excess of barium chloride solution.

98 g of a sulfuric acid solution was mixed with an excess of barium chloride solution. A precipitate with a mass of 23.3 g fell out. Calculate the mass fraction of sulfuric acid in the original solution.

Barium chloride reacts with sulfuric acid. This forms a water-insoluble barium sulfate salt, which precipitates. The reaction is described by the following chemical reaction equation.

BaCl2 + H2SO4 = BaSO4 + 2HCl;

Barium chloride reacts with sulfuric acid in equal molar amounts. This produces an equal amount of insoluble salt.

Find the chemical amount of barium sulfate.

M BaSO4 = 137 + 32 + 16 x 4 = 233 grams / mol;

N BaSO4 = 23.3 / 233 = 0.1 mol;

Find the weight of the same amount of sulfuric acid.

M H2SO4 = 2 + 32 + 16 x 4 = 98 grams / mol; m H2SO4 = 0.1 x 98 = 9.8 grams;

The acid concentration will be 9.8 / 98 = 0.1 = 10%;