How many liters of 0.1 normal silver nitrate solution is required to interact with 0.5 liters of 0.3 normal aluminum chloride solution?
November 29, 2020 | education
| In order to find out, we will compose an equation and solve it, and as a result we will find out the answer to the question:
V (AgNO3) = (Vх.а. * Nх.а.) / N (AgNO3) = 0.5 * 0.3 / 0.1 = 1.5Н
One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.