How much magnesium can react with a solution containing 19.8 g of sulfuric acid?
June 18, 2021 | education
| How much magnesium can react with a solution containing 19.8 g of sulfuric acid? The reaction products are magnesium sulfate and hydrogen.
Magnesium dissolves in sulfuric acid solution. The reaction is described by the following chemical equation:
Mg + H2SO4 = MgSO4 + H2 ↑;
Let’s determine the chemical amount of sulfuric acid.
For this purpose, we divide its weight by the weight of 1 mole of acid.
M H2SO4 = 2 + 32 + 16 x 4 = 98 grams / mol;
N H2SO4 = 19.8 / 98 = 0.202 mol;
The same amount of magnesium will react.
Let’s calculate its mass.
To do this, we multiply the molar amount of the substance by the weight of 1 mole of metallic magnesium.
M Mg = 24 grams / mol;
m Mg = 0.202 x 24 = 4.849 grams;
One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.