Calculate the mass and volume of carbon dioxide and the mass of water that are formed during
Calculate the mass and volume of carbon dioxide and the mass of water that are formed during the combustion of 36 g of methane
To solve the problem, we compose an equation according to the condition of the problem:
X l. -?
m = 36 g. X g. -?
1. СН4 + 2О2 = СО2 + 2Н2О + Q – combustion is accompanied by the release of heat, carbon dioxide, water;
2. Calculations:
M (CH4) = 16 g / mol;
M (CO2) = 44 g / mol.
3. Determine the amount of the original substance:
Y (CH4) = m / M = 36/16 = 2.25 mol;
Y (CO2) = 2.25 mol since the amount of substances according to the equation is 1 mol.
4. Find the mass, volume of the product:
m (CO2) = Y * M = 2.25 * 44 = 99 g;
Y (CO2) = 2.25 * 22.4 = 50.4 liters.
Answer: obtained carbon monoxide weighing 99 g, volume – 50.4 liters.