An electron moves in a magnetic field with an induction of 1 mT along a circle
An electron moves in a magnetic field with an induction of 1 mT along a circle with a radius of 0.5 cm, which is the kinetic energy of the electron.
m = 9.1 * 10 ^ -31 kg.
q = 1.6 * 10 ^ -19 Cl.
B = 1 mT = 1 * 10 ^ -3 T.
r = 0.5 cm = 5 * 10 ^ -3 m.
Ek -?
The kinetic energy of a body Ek of mass m, which moves with a speed V, is determined by the formula: Ek = m * V ^ 2/2.
The electron is acted upon by the Lorentz force F: F = q * V * B.
m * a = q * V * B – 2 Newton’s law.
We write the centripetal acceleration a according to the formula: a = V ^ 2 / r.
m * V2 / r = q * V * B.
V = q * B * r / m.
Ek = m * (q * B * r) ^ 2/2 * m ^ 2 = (q * B * r) ^ 2/2 * m.
Ek = (1.6 * 10 ^ -19 Kl * 1 * 10 ^ -3 T * 5 * 10 ^ -3 m) 2/2 * 9.1 * 10 ^ -31 kg = 3.5 * 10 ^ – 19 J.
Answer: the electron has kinetic energy Ek = 3.5 * 10 ^ -19 J.