An iron nail was heated in the air. How much dm3 of xylogen was involved in the reaction

An iron nail was heated in the air. How much dm3 of xylogen was involved in the reaction, if 0.29 g of oxide was formed. 3Fe + 2O2 = Fe3O4

Let us determine the amount of the substance of the formed iron oxide n (o) = m (o) / M (o), where m (o) and M (o) are the mass and molar mass of iron oxide, respectively.

n (o) = 0.29 / 232 = 0.00125 mol

According to the reaction equation, it can be seen that the formation of such an amount of iron oxide requires 2 times more mol of oxygen, then the amount of oxygen substance n (k) = n (o) * 2 = 0.00125 * 2 = 0.0025 mol

Let us find the required volume of oxygen under normal conditions V (k) = Vm * n (k), where Vm is the molar volume.

V (c) = 0.0025 * 22.4 = 0.056 dm3