What mass of methane will be obtained by fusing 120 grams of CH3COONa
July 24, 2021 | education
| What mass of methane will be obtained by fusing 120 grams of CH3COONa (sodium acetate) with alkali, if the mass fraction of methane yield is 95%?
Let’s implement the solution:
According to the condition of the problem, we write down the equation of the process:
CH3COONa + NaOH = CH4 + Na2CO3 – exchange, methane was obtained;
Calculations:
M (CH3COONa) = 81.9 g / mol;
M (CH4) = 16 g / mol;
Y (CH3COONa) = m / M = 120 / 81.9 = 1.46 mol;
Y (CH4) = 1.46 mol so the amount of substances is 1 mol.
Find the mass of the product:
m (CH4) = Y * M = 1.46 * 16 = 23.36 g (theoretical weight);
m (CH4) = 0.95 * 23.36 = 22.19 g (practical weight).
Answer: the mass of methane is 22.19 g
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