Find the volume of butane if 176 g of carbon dioxide was released during its combustion.
July 25, 2021 | education
| The reaction equation for the combustion of butane is as follows
2 С4Н10 + 9 О2 = 4 СО2 + 10 Н2О
Based on the reaction equation, it can be seen that the amount of butane substance is two times less than the amount of carbon dioxide. (4 mol: 2 mol = 2)
Let’s calculate how much carbon dioxide is released. Molar mass of carbon dioxide = 44 g / mol.
N = 176/44 = 4 mol of carbon dioxide was released.
Accordingly, the amount of butane substance will be 2 times less: 4/2 = 2 mol.
According to Avogadro’s law, 1 mole of any gas under normal conditions. occupies a volume of 22.4 liters. Therefore, 2 moles of butane will take 22.4 * 2 = 44.8 liters
Answer: the volume of butane is 44.8 liters
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