How many grams of acetaldehyde can be obtained from 75.3 g of calcium carbide containing 15% impurities?
July 29, 2021 | education
| To solve, we write down the equations of the process:
m = 75.3 g; 15% impurity
CaC2 + 2H2O = Ca (OH) 2 + C2H2 – hydration, acetylene obtained;
С2Н2 + Н2О = Н2С = СНОН (vinyl alcohol) = СН3 – СОН – acetaldehyde was formed;
Calculations:
M (CaC2) = 64 g / mol;
M (C2H4O) = 44 g / mol;
m (CaC2) = 75.3 * (1 – 0.15) = 64 g (weight without impurity);
Y (CaC2) = m / M = 64/64 = 1 mol;
Y (C2H4O) = 1 mol so the amount of substances is equal to 1 mol.
Find the mass of the product:
m (C2H4O) = Y * M = 1 * 44 = 44 g
Answer: the mass of acetaldehyde is 44 g
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