To 220 g of a sixty percent solution of acetic acid, 10 g of the substance and 50 g of water were added.
August 24, 2021 | education
| To 220 g of a sixty percent solution of acetic acid, 10 g of the substance and 50 g of water were added. Determine the new mass fraction.
Given:
m (solution) = 220 g;
w% (CH3COOH) = 60%;
m (CH3COOH) = 10 g;
m (H2O) = 50 g;
Find:
w% (CH3COOH in final solution) -?
Solution:
1) Find the mass of acid in solution:
m (CH3COOH) = 220 g * 0.6 = 132 g;
2) Find the mass of the solution after adding a portion of acid and water:
m (solution) = 220 g + 10 g + 50 g = 280 g;
3) Find the mass of acid in the new solution:
m (CH3COOH) = 132 g + 10 g = 142 g;
4) Find the mass fraction of acetic acid in the resulting solution:
w% (CH3COOH) = m (CH3COOH): m (solution) * 100% = 142 g: 280 g * 100% = 50.7%.
Answer: w% (CH3COOH) = 50.7%.
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