Carry out the transformations: Al – Al2O3 – AlCl3 – Al (OH) 3 – NaAlO2. Give the reaction equations

| August 29, 2021 | education

Carry out the transformations: Al – Al2O3 – AlCl3 – Al (OH) 3 – NaAlO2. Give the reaction equations in molecular and ionic form.

Al  → Al2O3 → AlCl3 → Al(OH) 3 → NaAlO2.

1.

4Al + 3O2 =  2Al2O3

2.

Al2O3  + 6HCl = 2AlCl3  +  3H2O

Al2O3  + 6H1+ + 6Cl1- = 2Al3++ 6Cl1- +  3H2O

Al2O3  + 6H1+  = 2Al3++  3H2O

3.

AlCl3  + 3NaOH = Al(OH)3 ↓+ 3NaCl

Al3+ + 3Cl1-  + 3Na1+ + 3OH1- = Al(OH)3 ↓+ 3Na 1++ 3Cl1- .

Al3+ + 3OH1- = Al(OH)3 ↓ .

4.

Al(OH)3 + NaOH = NaAlO2 + 2H2O.

Al(OH)3 + Na1+ + OH1- = Na1+ + AlO21- + 2H2O.

Al(OH)3 + OH1- = Na1+ + AlO21- + 2H2O.



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