Calculate the amount of substance and the mass of magnesium carbonate formed
September 4, 2021 | education
| Calculate the amount of substance and the mass of magnesium carbonate formed by the interaction of magnesium hydroxide with 10 g of carbon monoxide
Given:
m (CO2) = 10 g
Find:
n (MgCO3) -?
m (MgCO3) -?
Solution:
1) Mg (OH) 2 + CO2 => MgCO3 + H2O;
2) n (CO2) = m (CO2) / M (CO2) = 10/44 = 0.2 mol;
3) n (MgCO3) = n (CO2) = 0.2 mol;
4) m (MgCO3) = n (MgCO3) * M (MgCO3) = 0.2 * 84 = 16.8 g.
Answer: The amount of MgCO3 substance is 0.2 mol; weight – 16.8 g.
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