What volume of hydrogen will be released when phosphoric acid interacts with magnesium weighing 6 grams?
September 9, 2021 | education
| The interaction of magnesium with phosphoric acid occurs in accordance with the following chemical reaction equation:
3Mg + 2H3PO4 = Mg3 (PO4) 2 + 3H2;
When 1 metal dissolves, 1 mol of hydrogen gas is released.
Let’s calculate the chemical amount of a substance in 6 grams of metal.
N Mg = 6/24 = 0.25 mol;
This amount of hydrogen will be released.
Let’s calculate its volume.
One mole of gas under normal conditions fills a volume of 22.4 liters.
The volume of hydrogen will be:
V H2 = 0.25 x 22.4 = 5.6 liters;
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