Find the volume of oxygen required to burn zinc with a mass of 65 grams.
September 11, 2021 | education
| m (Zn) = 65 g.
Let’s determine the volume of oxygen that has reacted. We write down the solution.
We write down the equation of reactions.
2Zn + O2 = 2ZnO.
Find the amount of zinc. We use the following formula.
n = m / M.
Where n is the amount of substance.
m is the mass of the substance.
M is the molar mass of the substance.
M (Zn) = 65.4 g / mol.
n = 65 / 65.4 = 0.99 mol.
Let us determine the amount of oxygen substance according to the reaction equation.
0.99 mol Zn – x mol О2
2 mol Zn – 1 mol О2
X = 0.99 * 1: 2 = 0.495 mol.
Next, we determine the volume of oxygen.
n = V / Vm.
V = n * Vm = 0.495 mol * 22.4 l / mol = 11.088 l.
Answer: V (O2) = 11.088 liters.
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