Find the perimeter and area of a rectangle that is 17/5 cm wide and 6 times its width.

Let’s find the length of the rectangle:
17/5 * 6 = 17/5 * 6/1 = 102/5 = 20 2/5;
Let’s find the perimeter of the rectangle, according to the formula: P = 2a + 2b,
P = 2 * 17/5 + 2 * 102/5;
1) 2 * 17/5 = 2/1 * 17/5 = 34/5 = 6 4/5;
2) 2 * 102/5 = 2/1 * 102/5 = 204/5 = 40 4/8;
3) 6 4/5 + 40 4/5 = 46 8/5 = 47 3/5;
P = 47 3/5 cm;
Let’s find the area of the rectangle, according to the formula: S = ab,
S = 17/5 * 47 3/5 = 17/5 * 238/5 = 4046/25 = 161 21/25 cm ^ 2.
Let’s convert 161 21/25 to a decimal fraction: 21/25 = 0.84, 161 21/25 = 161.84.
161.84 cm ^ 2 = 1.62 dm ^ 2. Or 161.84 cm ^ 2 = 1 dm ^ 2 = 61.84 cm ^ 2.
Answer: P = 47 3/5 cm, S = 1 dm ^ 2 61.84 cm ^ 2.