The car, moving evenly at a speed of 30 m / s, develops a traction force of 1.2 kN. Find the engine power.
September 20, 2021 | education
| Given: speed v = 30 m / s.
Traction force F = 1.2 kN = 1200 N, (1 kN = 1000 N).
Find: Power N.
Solution:
Power = mechanical work / time.
N = A / t; A = F * S; therefore, N = F * S / t = F * v.
N = 30 * 1200 = 36000 (W) = 36 (kW).
The engine power with a uniform movement of the car is 36 kW.
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