In a rectangular trapezoid ABCK, the smaller side is 6 cm and the height CH divides the base of AK

In a rectangular trapezoid ABCK, the smaller side is 6 cm and the height CH divides the base of AK in half. Find the area of the trapezoid.

In the ABCK trapezoid, the base BC = 6 cm, the base of the AK is 2 times larger than the smaller base.
According to the condition, the smaller side AB is 6 cm, but the trapezoid is rectangular, and the smaller side of the trapezoid is the height of the trapezoid. And the larger base of the trapezoid (AK) is twice the size of the smaller base (BC).
AK = 2 * (BC) = 2 * 6 = 12 (CM).
Area of the trapezoid = the product of the height and the half-sum of the bases of the trapezoid.
Area = [(BC + AK) / 2] * AB = [(6 + 12) = 54 (cm) * (cm) = 54 cm sq.