A ball weighing 100 g fell from a height of 10 m and jumped to a height of 7 m. How much heat was released during this?

Initial data: m (ball mass) = 100 g (0.1 kg); h1 (the height from which the ball fell) = 10 m; h2 (the height the ball bounced to) = 7 m.

Reference values: g (acceleration due to gravity) ≈ 1 0m / s2.

The heat released when the ball is hit will be equal to the difference in the potential energy of the ball at a height of 10 m and 7 m: E = En1 – En2 = m * g * h1 – m * g * h2 = m * g * (h1 – h2).

Calculation: E = 0.1 * 10 * (10 – 7) = 3 J.

Answer: When the ball was hit, 3 J of heat was released.