We hung the load on the dynamometer, its reading was equal to 24.5 Newtons. Determine the mass
November 20, 2020 | education
| We hung the load on the dynamometer, its reading was equal to 24.5 Newtons. Determine the mass of the load suspended from the dynamometer.
F = 24.5 N.
g = 9.8 m / s ^ 2.
m -?
The body that hangs on the dynamometer is acted upon by 2 forces: the force of gravity m * g, directed vertically downward, and the force of elasticity of the spring of the dynamometer F, directed vertically upward.
Since the load is in equilibrium, these forces compensate each other: F = m * g.
m = F / g.
m = 24.5 N / 9.8 m / s ^ 2 = 2.5 kg.
Answer: the weight of the body that hangs on the dynamometer is m = 2.5 kg.
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