The stone is thrown at an angle of 20 degrees to the horizon with an initial speed of 13 m / s
The stone is thrown at an angle of 20 degrees to the horizon with an initial speed of 13 m / s. Determine the maximum height of the stone to rise?
∠α = 20 °.
V0 = 13 m / s.
g = 9.8 m / s2.
hmax-?
The motion of a stone can be divided into two types: horizontally, it moves uniformly at a speed V0х, vertically uniformly accelerated with an acceleration of gravity g and an initial speed V0у.
V0х = V0 * cosα.
V0у = V0 * sinα.
The height of the stone lifting h is expressed by the formula: h = (V0у ^ 2 – Vу ^ 2) / 2 * g, where V0у, Vу are the initial and final vertical component of the stone speed.
At the maximum height hmax, the stone stops Vу = 0 m / s, the formula will take the form: hmax = V0у ^ 2/2 * g = (V0 * sinα) ^ 2/2 * g.
hmax = (13 m / s * sin20 °) ^ 2/2 * 9.8 m / s2 = 1 m.
Answer: the maximum height of the stone lifting is hmax = 1 m.