What volume of hydrogen will be released when aluminum is dissolved in 43.8 g of 20% hydrochloric acid solution?
February 11, 2021 | education
| The reaction of aluminum with hydrochloric acid is described by the following chemical reaction equation.
Al + 3HCl = AlCl3 + 1.5 H2;
When 1 mol of aluminum is dissolved, 1.5 mol of hydrogen is released. This requires 3 mol of hydrochloric acid.
Determine the amount of the substance contained in 43.8 grams of a 20% hydrochloric acid solution.
M HCl = 1 + 35.5 = 36.5 grams / mol;
m HCl = 43.8 x 0.2 = 8.76 grams;
N HCl = 8.76 / 36.5 = 0.24 mol;
Reaction with 0.24 mol of hydrochloric acid with sufficient aluminum will result in 0.12 mol of hydrogen.
One mole of ideal gas under normal conditions takes a volume of 22.4 liters.
Let’s determine the volume of hydrogen.
V H2 = 0.12 x 22.4 = 2.688 liters;
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