How much hydrogen will be released when 3 g of zinc interact with water?
February 17, 2021 | education
| m (Zn) = 3 g.
Determine the volume of hydrogen that will result from the reaction. We write down the resulting reaction equation.
Zn + 2HOH = Zn (OH) 2 + H2.
First, we find the amount of zinc. We write down the solution.
n = m / M.
M (Zn) = 65 g / mol.
n (Zn) = 3 g / 65 g / mol = 0.09 mol.
Further, according to the reaction equation, we find the amount of hydrogen substance.
0.09 mol Zn – x mol H2
1 mol Zn – 1 mol H2
Find the unknown value of x.
X = 0.09 * 1: 1 = 0.09 mol.
Find the volume of hydrogen.
n = V / Vm.
V = n * Vm = 0.09 * 22.4 = 2.1 liters.
Answer: the volume of hydrogen is 2.1 liters.
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