What volume of gas is formed by the interaction of a 200 g nitric acid solution with a 0.315 mass fraction
February 26, 2021 | education
| What volume of gas is formed by the interaction of a 200 g nitric acid solution with a 0.315 mass fraction of acid with potassium sulfide?
1. The interaction of nitric acid with potassium sulfide proceeds according to the equation:
2HNO3 + K2S = 2KNO3 + H2S ↑;
2. find the mass of nitric acid:
m (HNO3) = w (HNO3) * m (solution) = 0.315 * 200 = 63 g;
3.Calculate the chemical amounts of nitric acid and the resulting hydrogen sulfide:
n (HNO3) = m (HNO3): M (HNO3);
M (HNO3) = 1 + 14 + 3 * 16 = 63 g / mol;
n (HNO3) = 63: 63 = 1 mol;
n (H2S) = n (HNO3): 2 = 1: 2 = 0.5 mol;
4. calculate the volume of hydrogen sulfide:
V (H2S) = n (H2S) * Vm = 0.5 * 22.4 = 11.2 liters.
Answer: 11.2 liters.
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