Determine the Archimedean force acting on a bar, the dimensions of which are 2 * 3 ^ 10 cm, in water.
Given:
a = 2 centimeters = 0.02 meters – the length of the bar;
b = 3 centimeters = 0.03 meters – the width of the bar;
c = 10 centimeters = 0.1 meter – the height of the bar;
ro = 1000 kg / m3 (kilogram per cubic meter) is the density of pure water.
It is required to determine F (Newton) – the Archimedean force acting on the bar when it is immersed in water.
Assuming that the bar has the shape of a rectangular parallelepiped, we determine its volume:
V = a * b * c = 0.02 * 0.03 * 0.1 = 0.0006 * 0.1 = 0.00006 m3.
Then, to determine the Archimedean force, you must use the following formula:
F = ro * V * g, where g = 9.8 Newton / kilogram;
F = 1000 * 0.00006 * 9.8 = 0.06 * 9.8 = 0.59 Newton (the result was rounded to one hundredth).
Answer: an Archimedean force of 0.59 Newton acts on the bar.