The equation of oscillation of a spring pendulum weighing 200 g has the form x = 0.05cos (8пt + п / 3).
March 1, 2021 | education
| The equation of oscillation of a spring pendulum weighing 200 g has the form x = 0.05cos (8пt + п / 3). Determine the stiffness of the spring if its mass can be neglected.
We need several formulas.
Let’s write the first one:
Ω = √ (k / m);
Now let’s write the equation of oscillations:
ω = 8π;
It remains only to square and equate:
k / m = 64 * π²;
Substitute the values into the formula and calculate:
k = 64 * π² * 0.200 ≈ 126 N / m;
Answer: k ≈ 126 N / m.
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