Determine the pressure that the kerosene exerts on the bottom of a 5m2 tank. The mass of kerosene in a tank is 500 kg.
March 1, 2021 | education
| Given:
s = 5 square meters – tank bottom area;
ro = 800 kilograms / cubic meter – density of kerosene;
m = 500 kilograms is the mass of kerosene;
g = 10 Newton / kilogram – acceleration of gravity.
It is required to determine P (Pascal) – the pressure that kerosene exerts on the bottom of the tank.
Let’s find the volume of kerosene:
V = m / ro.
Then the height of the column of kerosene in the tank will be equal to:
h = V / s = m / (ro * s).
The pressure of kerosene at the bottom of the tank will be equal to:
P = ro * g * h = ro * g * m / (ro * s) = g * m / s;
P = 10 * 500/5 = 5000/5 = 1000 Pascal.
Answer: the pressure is 1000 Pascal.
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