The voltage at the ends of an iron conductor 120 cm long is 60 V. Determine the current
March 3, 2021 | education
| The voltage at the ends of an iron conductor 120 cm long is 60 V. Determine the current in the conductor if the wire cross-section is 0.025 mm 2.
According to Ohm’s Law:
I = U / R, where I is the current in the conductor, U is the voltage at the ends of the iron conductor (U = 60 V), R is the resistance of the iron conductor.
R = ρ * l / S, where ρ is the resistivity of the iron conductor (ρ = 0.098 Ohm * mm ^ 2 / m), l is the length of the iron conductor (l = 120 cm = 1.2 m), S is the cross-sectional area of the iron conductor (S = 0.025 mm ^ 2).
Let’s calculate the current in the conductor:
I = U * R = U / (ρ * l / S) = U * S / (ρ * l) = 60 * 0.025 / (0.098 * 1.2) = 12.76 A.
Answer: The current strength is 12.76 A.
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