How many grams of sodium sulfide will be obtained when 64 g sulfur reacts with sodium?
March 24, 2021 | education
| Let’s write the reaction equation:
2Na + S = Na2S
Let’s find the amount of sulfur substance:
v (S) = m (S) / M (S) = 64/32 = 2 (mol).
According to the reaction equation, 1 mole of Na2S is formed per 1 mole of S, therefore:
v (Na2S) = v (S) = 2 (mol).
Thus, it is possible to obtain sodium sulfide with a mass:
m (Na2S) = v (Na2S) * M (Na2S) = 2 * 78 = 156 (g).
Answer: 156
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