A metal part weighs 48.5 N in air, and when immersed in kerosene, it weighs 44.5 N.
April 1, 2021 | education
| A metal part weighs 48.5 N in air, and when immersed in kerosene, it weighs 44.5 N. What is the Archimedean force acting on a part?
Given:
P1 = 48.5 Newton – weight of a metal part measured in air;
P2 = 44.5 Newton – the weight of a metal part, measured when immersed in kerosene.
It is required to determine Farchimedes (Newton) – the Archimedean force acting on the part.
According to Newton’s first law, we have:
P2 = F gravity – Farchimedes.
Since in this case F gravity = P1, then:
P2 = P1 – Farchimedes, from here we find that:
Farchimedes = P1 – P2 = 48.5 – 44.5 = 4 Newtons.
Answer: an Archimedean force equal to 4 Newtons acts on a metal part.
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