A 10 kg load is suspended from one end of the rope thrown over the block. How much weight must be suspended
| February 23, 2021 | education
A 10 kg load is suspended from one end of the rope thrown over the block. How much weight must be suspended from the other end of the thread for the weight to rise with an acceleration of 2 m / s2?
m1 = 10 kg.
g = 10 m / s2.
a = 2 m / s2.
m2 -?
Loads will move with the same acceleration, only a load with mass m1 upwards, and a load with mass m2 downwards.
If we neglect the mass of the fixed block, then 2 Newton’s law will have the form: a * (m1 + m2) = m1 * g – m2 * g.
a * m1 + a * m2 = m1 * g – m2 * g.
a * m2 + m2 * g = m1 * g – m1 * a.
m2 * (g + a) = m1 * (g – a).
m2 = m1 * (g – a) / (g + a).
m2 = 10 kg * (10 m / s2 – 2 m / s2) / (10 m / s2 + 2 m / s2) = 6.6 kg.
Answer: the mass of the second load is m2 = 6.6 kg.
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