A 10% sulfuric acid solution weighing 500 g is given. 0.5 L of water was added to the solution.

A 10% sulfuric acid solution weighing 500 g is given. 0.5 L of water was added to the solution. What is the concentration of the resulting diluted solution?

Let’s solve the problem

Initial solution mass = 500 g.

Mass fraction of solute = 10%

Therefore, the mass of the substance = 500 * 0.1 = 50 g.

500 ml of water (0.5 l) was added to the solution, and 1 ml of pure water under normal conditions weighs 1 g. Therefore, the mass of the solution began to equal: 500 + 500 = 1000 g.

Let’s calculate the mass fraction of the resulting solution: 50/1000 = 0.05 or 5%.

Answer: the resulting solution has a concentration of 5%.