A 100 KB file is transferred over the connection at a speed of 3600 bits per second

A 100 KB file is transferred over the connection at a speed of 3600 bits per second. Determine how many KB less can be transferred in the same time at a rate of 1440 bits per second.

First, let’s find the time it took for the file to be transmitted at a speed of 3600 bps.

t = const = I1 / v1 = 100 kB / 3600 bit / s = (100 * 1024 * 8) bit / 3600 bit / s = (1024 * 2/9) sec.

I2 = t * v2 = (1024 * 2/9) s * 1440 bps = 327680 bits = 327680 / (1024 * 8) kB = 40 kB.

I1 – I2 = 100KB – 40KB = 60KB.

Answer: You can transfer a file that is 60 KB smaller.



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