A 100 kg load lies on the elevator floor. Determine the acceleration of the lift if the load presses on the floor with a force of 1200 N.

Task data: m (cargo weight) = 100 kg; F (force acting on the floor of a moving elevator from the side of the load) = 1200 N.

Constants: according to the condition g (gravitational acceleration) = 9.8 m / s2.

The acceleration of the elevator in question can be determined from the formula: m * a = P – N = F – m * g, whence m = (F – m * g) / m.

Let’s make the calculation: m = (1200 – 100 * 9.8) / 100 = 2.2 m / s2.

Answer: The acceleration of the elevator in question is 2.2 m / s2.