A 12.5 Ohm light bulb is connected to a battery with an EMF of 4.8 V and an internal resistance
| April 26, 2021 | education
A 12.5 Ohm light bulb is connected to a battery with an EMF of 4.8 V and an internal resistance of 3.5 ohms. Determine the battery current.
Initial data: Eis (battery EMF) = 4.8 V; r (internal resistance of the battery) = 3.5 ohms; R (the resistance of the light bulb connected to the battery) = 12.5 ohms.
The current strength in the battery under consideration is determined using the formula: I = Еis / (r + R).
Calculation: I = 4.8 / (3.5 + 12.5) = 4.8 / 16 = 0.3 A.
Answer: The current in the battery under consideration will be 0.3 A.
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