A 15KB file is transferred over a connection in 40 seconds. Determine the size of the file, in KB, that can be transferred over another connection at triple the speed in 8 seconds.
First, you need to convert the specified file size from kilobytes to bytes.
Since 1 KB contains 1024 bytes, we get:
15 * 1024 = 15360 bytes.
Find the initial transfer rate.
To do this, we divide the file size by the time of its transfer, namely 40 seconds.
15360/40 = 384 bytes per second.
Find the value of three times the file transfer rate.
384 * 3 = 1152 bytes per second.
Thus, the size of the file that can be transferred in 8 seconds will be:
1152 * 8 = 9216 bytes.
In kilobytes we get:
9216/1024 = 9 KB.
Answer: 9 KB.
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