A 2 ohm resistance conductor carries a current of 500 mA. What is the voltage at the ends of this conductor?
| February 7, 2021 | education
These tasks: R (resistance of the considered conductor) = 2 Ohm; I (the amount of current that flows through the conductor) = 500 mA (0.5 A).
The voltage at the ends of the conductor in question can be defined as the product of its resistance and current strength: U = I * R.
Calculation: U = 0.5 * 2 = 1 V.
Answer: The effective voltage at the ends of the conductor is 1 V.
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