A 20 Ohm heater is connected to the terminals of the current source with an EMF of 220 V

A 20 Ohm heater is connected to the terminals of the current source with an EMF of 220 V and an internal resistance of 1.2 Ohm. Determine the amount of heat generated by the heater in 2 minutes.

Initial data: Eis (EMF in the current source) = 220 V; r (internal resistance of the source) = 1.2 Ohm; R (heater resistance, external resistance) = 20 Ohm; t (duration of heater operation) = 2 min (120 s).

1) Determine the current in the created circuit: I = 220 / (1.2 + 20) = 10.38 A.

2) The amount of heat that the heater will release in 2 minutes: Q = I ^ 2 * R * t = 10.38 ^ 2 * 20 * 120 ≈ 260 kJ.

Answer: In 2 minutes, the heater will release 260 kJ of heat.