# A 200 m long train enters a 300 m long tunnel moving uniformly at a speed of 10 m / s.

October 14, 2021 | education

| **A 200 m long train enters a 300 m long tunnel moving uniformly at a speed of 10 m / s. How long will it take for the train to fully exit the tunnel?**

Task data: Lp (train length) = 200 m; Lt (tunnel length) = 300 m; V (constant speed) = 10 m / s (uniform movement).

The time it took for a given train to exit the tunnel is calculated by the formula: t = S / V = (Lt + Lp) / V.

Let’s make a calculation: t = (300 + 200) / 10 = 500/10 = 50 s.

Answer: The target train will exit the tunnel in 50 seconds.

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