A 20KB file is transferred over some connection at 1024 bits per second.

A 20KB file is transferred over some connection at 1024 bits per second. Determine how many seconds faster you can transfer the same file over another connection at 2048 bits per second.

To solve this problem, you first need to convert the specified file size from kilobytes to bits.

Since 1 KB contains 1024 bytes, and 1 byte contains 8 bits, we get:

20 * 1024 * 8 = 163840 bits.

Determine the time to transfer the file through the first connection.

Divide the file size by the transfer rate.

163840/1024 = 160 seconds.

Find the time to transfer the file through the second connection.

163840/2048 = 80 seconds.

The difference in transmission time will be:

160 – 80 = 80 seconds.

Answer: 80 seconds.