A 250 ml solution contains 0.004 g of H2Cr2O7. Find pH, pOH?

Let’s find the molar concentration of hydrogen ions. Since H2Cr2O7 is a strong acid and its complete dissociation occurs in an aqueous solution: [H +] = 2 * c (H2Cr2O7) = 2 * m (H2Cr2O7) / M (H2Cr2O7) / V (solution) = 2 * 0.004 / 118 / 0.25 = 2.7 * 10-4

pH = -lg (2.7 * 10-4) = 3.56

pOH = 14 – 3.56 = 10.44



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