A 30 μF capacitor was connected to a 200V source. Determine the energy of the charged condensate.

We calculate the energy of a charged capacitor using the following formula:

W = C * U ^ 2/2, where C is the electrical capacity of a given capacitor (C = 30 μF = 30 * 10 ^ -6 F), U is the voltage at the source, the potential difference (U = 200 V).

Let’s perform the calculation:

W = C * U ^ 2/2 = 30 * 10 ^ -6 * 200 ^ 2/2 = 0.6 J.

Answer: The energy of a charged capacitor is 0.6 J.