A 4 g weighed portion of calcium was dissolved in 1 L of water. Calculate the mass fraction
A 4 g weighed portion of calcium was dissolved in 1 L of water. Calculate the mass fraction of calcium hydroxide in the resulting solution.
The mass fraction of a substance is calculated by the formula:
W = m (substance): m (solution) × 100%,
m (solution) = m (substance) + m (water).
m (water) = V p.
m (water) = 1l × 1 = 1 kg = 1000 g.
Let’s find the amount of calcium substance.
n = m: M.
M (Ca) = 40 g / mol.
n = 4 g: 40 g / mol = 0.1 mol.
Let’s compose the reaction equation, find the quantitative ratios of substances.
Ca + 2H2O = Ca (OH) 2 + H2 ↑.
1 mole of calcium accounts for 1 mole of calcium hydroxide. The substances are in quantitative ratios 1: 1. The amount of the substance will be the same.
n (Ca) = n (Ca (OH) 2) = 0.1 mol.
Let us find the mass of Ca (OH) 2.
m = n M.
M (Ca (OH) 2) = 40 + 34 = 74 g / mol.
m = 0.1 mol × 74 g / mol = 7.4 g.
m (solution) = 1000 g + 7.4 g = 1007.4 g.
W = (7.4: 1007.4) × 100% = 0.735%.
Answer: W = 0.735%.