A 400 g hammer strikes a nail and drives it into the board. The speed of the hammer before the blow is 5 m / s

| September 7, 2021 | education

A 400 g hammer strikes a nail and drives it into the board. The speed of the hammer before the blow is 5 m / s, after the blow – 0 m / s. What is the average impact force of a hammer if the impact duration is 0.1 s?

m = 400 g = 0.4 kg.

V0 = 5 m / s.

V = 0 m / s.

t = 0.1 s.

F -?

According to 2 Newton’s law, the force F, which acts on a body, is equal to the product of the body’s mass m by its acceleration a: F = m * a.

The acceleration of the body a will be expressed by the formula: a = (V0 – V) / t, where V0, V are the initial and final velocity of the body, t is the time of the change in velocity.

The average hammer impact force F will be expressed by the formula: F = m * (V0 – V) / t.

F = 0.4 kg * (5 m / s – 0 m / s) / 0.1 s = 20 N.

Answer: the average force of a hammer blow on a nail head is F = 20 N.



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