A 5 liter bottle contains 3 grams of oxygen. Determine the pressure in the cylinder at 17 degrees Celsius.

To find the value of the taken oxygen pressure in the indicated cylinder, we use the Mendeleev-Clapeyron equation: P = m * R * T / (V * MO2).

Constants and variables: m is the mass of taken oxygen (m = 3 g); R – universal gas constant (R = 8.31 J / (K * mol)); T – abs. oxygen temperature (Т = 290 К (17 ºС)); V is the capacity of the cylinder (V = 5 l = 0.005 m3); MO2 – molar mass (MO2 = 32 g / mol).

Let’s calculate: P = m * R * T / (V * MO2) = 3 * 8.31 * 290 / (0.005 * 32) = 45185.625 Pa ≈ 45.2 kPa.

Answer: The pressure of the taken oxygen in the indicated cylinder is 45.2 kPa.