A 500 m3 balloon is filled with helium under a pressure of 10^5 Pa. As a result of solar heating, the temperature of the gas

| June 17, 2021 | education

A 500 m3 balloon is filled with helium under a pressure of 10^5 Pa. As a result of solar heating, the temperature of the gas in the balloon rose from 10 ° C to 25 ° C. How much has the internal energy of the gas increased?

These tasks: V (volume of the considered balloon) = 500 m3; P1 (initial pressure) = 10 ^ 5 Pa; T1 (initial temperature of helium) = 10 ºС = 283 K; T2 (end temperature) = 25 ° C = 298 K.

Constants: i (number of degrees of freedom of helium gas) = 3.

The increase in the internal energy of helium in the considered balloon is determined by the formula: ΔU = 0.5 * i * (m / M) * R * ΔT = 0.5 * i * P * V / T1 * (T2 – T1).

Calculation: ΔU = 0.5 * 3 * 10 ^ 5 * 500/283 * (298 – 283) = 3.98 * 10 ^ 6 J.

Answer: The internal energy of helium gas in the considered balloon has increased by 3.98 MJ.



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